The discussion revolves around the concepts of torque and rotation in the context of a rod subjected to forces. Participants are examining the implications of ignoring the weight of the rod and how it affects the overall force and torque calculations.
Some participants have provided insights into the relationship between force and torque, noting that while the sum of forces may be zero, the torque can still be non-zero due to the lines of application of the forces. There is an ongoing exploration of how the pivot point affects the rotation of the rod.
There is a mention of the rod lying flat on a table and the need to consider the normal force and gravitational force acting on it. Participants are also reflecting on the implications of the pivot point's location, which has not been explicitly defined in the problem.
The rod is lying on a table. If you want to account for gravity, there is another force that you also need to account for...SakuRERE said:
The rod is flat on the table, the weight is acting perpendicular to the table and is offset by the normal force from the table. The rod in your image is seen from above, both forces and the rod are to be considered to be in the horizontal plane. The vertical direction is therefore irrelevant.SakuRERE said:
jbriggs444 said:
ohh yeaah, thanks everyone. i didn't focus on that point that is layning in the table!Orodruin said:
and regarding the pivot point, i think it's the one who will decide if it will rotate or not, i mean if it was at the center of the rod than there should be not rotation, but if the pivot is not in the center (not mentioned) then the distance of each force to the pivot won't be same so then i would say there rotation. but the one answering the question didn't specify any thing !SakuRERE said:
Your reference point does not matter at all. The way you choose your reference point (which is arbitrary) cannot affect what physically happens to the rod.SakuRERE said:
Orodruin said:
thanks thanks thanks very much sirOrodruin said:
