1. The problem statement, all variables and given/known data A baseball is hit with an initial velocity of 103 ft/sec, with an initial height of 3 ft, and at an angle of 41 degrees. There is a wind blowing 22ft/sec in the direction opposite to the horizontal path of the ball at an angle of depression of 12 degrees. Assume that gravity is the only force affecting the path of the ball. Disregard air resistance and spin. 2. Relevant equations V=Velocity For the X equation it should be Vcos(D)T where D=the degree at which the baseball is hit and T=time For the y equation it should be Vsin(D)T - 16t^2 + initial height 3. The attempt at a solution I know that if the wind was blowing exactly horizontally then the equation for X would be X=103cos(41)T - 22. But, I'm not sure how the wind's angle of depression would affect this. It also has to alter the equation for Y since the wind blows downwards so the height will go down. Can someone explain how to account for the wind's angle of depression? Thank you.