- #1
Anarion
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A baseball (4oz .00781 slugs) is thrown at 60 ft/s. After it strikes the bat it is hit at 40 degrees to the initial trajectory (towards third base) and then has a velocity of 120 ft/s. What is the magnitude of the average force applied? T=0.02 sec.
2. F delta T = m delta V
3. Delta Vx= 120 cos 40 - (-60) = 151.9
Delta Vy= 120 sin 40 = 77.13
DeltaV=Square root(1519.9^2+77.1362^2)=170.4
F= .00781*170.4/.02sec =66.5 ft lb
This does not seem right to me. Any help would be appreciated.
2. F delta T = m delta V
3. Delta Vx= 120 cos 40 - (-60) = 151.9
Delta Vy= 120 sin 40 = 77.13
DeltaV=Square root(1519.9^2+77.1362^2)=170.4
F= .00781*170.4/.02sec =66.5 ft lb
This does not seem right to me. Any help would be appreciated.
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