What Is the Average Force Exerted by the Bat on the Baseball?

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SUMMARY

The average force exerted by the bat on a 150-g baseball, pitched at 40 m/s and hit back at 60 m/s, is calculated using the formula Favg = delta p / delta t. The correct change in momentum (delta p) is determined by considering the direction of the velocities, resulting in delta p = 0.150 kg * (60 - (-40)) m/s = 15 kg·m/s. With a contact time of 5 ms, the average force is calculated as Favg = 15 / 0.005 = 3000 N.

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-EquinoX-
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Homework Statement


A 150-g baseball pitched at a speed of 40 m/s is hit straight back to the pitches at a speed of 60 m/s. If the bat is in contact with the baseball for 5 ms calculate the magnitude of the average force exerted by the bat on the baseball.


Homework Equations


Favg = delta p/ delta t


The Attempt at a Solution


delta p = m (Vf-Vi) = 0.150(60-40) = 3
Favg = 3/0.005 = 3

however the answer is 3000N, can anyone clarify where I made the mistake?
 
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-EquinoX- said:

Homework Statement


A 150-g baseball pitched at a speed of 40 m/s is hit straight back to the pitches at a speed of 60 m/s. If the bat is in contact with the baseball for 5 ms calculate the magnitude of the average force exerted by the bat on the baseball.


Homework Equations


Favg = delta p/ delta t


The Attempt at a Solution


delta p = m (Vf-Vi) = 0.150(60-40) = 3

One of the values you have put in for the velocities is not correct. Remember that you have to account for the direction of the ball with the appropriate sign.
 
oh thanks for pointing that out, it should be 60-(-40)
 

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