You and a friend stand on a snow-covered roof. You both throw snowballs from an elevation of 15 m with the same initial speed of 13 m/s, but in different directions. You through your snowball downward, at 40° below the horizontal; your friend throws her snowball upward, at 40° above the horizontal. What is the speed of each ball when it is 5.0 m above the ground? (Neglect air resistance.)
m/s(your friend's snowball)
The Attempt at a Solution
well this is online and im only given 5 tries to get the correct answer and unfortunately i used up my 5 tries for the first part :(
but anyways i tried finding the time the snowball is 5m from the ground and i used the y=y_0+V_0(t)-1/2gt^2 but im not sure what i should use for the y_0 and V_0, i would say y_0 would be 15 and V_0 would be V_0sin(theta) or 13sin40, then g would be 9.8 and y=5 so then i can solve for t? then after finding t do i just use V_f=V_0+at to get the velocity of the snowball when its 5 m above the ground?