This is a really basic problem but the answers I've gotten don't match up with the back of the book. I've been over it several times & can't understand where I'm going wrong - any pointers would be much appreciated! 1. The problem statement, all variables and given/known data A physics book slides off a horizontal tabletop with a speed of 1.40m/s. It strikes the floor in 0.320s. Ignore air resistance. Find a) the height of the tabletop off the floor; b) the horizontal distance from the edge of the table to the point where the book strikes the floor. 2. Relevant equations vf = vi + at x = xi + vit + ½at2 3. The attempt at a solution I broke up the book's initial velocity into components: Vf-x = Vi-x = 1.40m/s Vf-y = Vi-y +at = -gt = -3.14m/s The height of the table = the magnitude of the vertical displacement y (using the top of the table as the origin): y = yi + Vi-yt + ½at2 = 0 + 0 + ½(-9.8m/s2)(0.320s)2= -0.502m -> height = 0.502m What the book gives for this is 1.13m. The horizontal distance = magnitude of horizontal displacement x: x = xi + Vi-xt + ½at2 = 0 + (1.40m/s)(0.320s) + 0 = 0.448m What the book gives here is 0.502m (which is what I got for the height - which means I'm either completely mixed up or maybe the book is wrong?!) Thanks for taking a look.