Basic molarity and dilution formulas

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Discussion Overview

The discussion revolves around calculating the amount of water needed to dilute 91% grain alcohol to a concentration of 70%. Participants explore different mathematical approaches, including dimensional analysis, ratios, and considerations of density and volume contraction.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses difficulty recalling basic math for dilution calculations and seeks assistance.
  • Another participant proposes a formula based on volume, suggesting that if the volume of water to add is v and the volume of 91% alcohol is Q, the equation 0.91/(Q+v)=0.71 can be used.
  • Some participants note that the question may not necessarily involve molarity and could be influenced by factors like densities or volume contraction changes when mixing alcohol with water.
  • A participant mentions initially considering a molality approach but found that using ratios and proportions was simpler for this problem.
  • There is a suggestion that focusing on moles or molarity complicates the question unnecessarily, as the original inquiry centers on concentration percentages.
  • One participant humorously reflects on their ability to perform complex calculus but struggles with basic dilution calculations.
  • Another participant humorously adds that the same approach could apply to other substances like rubbing alcohol and jet fuel.

Areas of Agreement / Disagreement

Participants express varying opinions on the best approach to solve the dilution problem, with some favoring ratios and proportions while others consider the implications of density and volume changes. No consensus is reached on a singular method or solution.

Contextual Notes

Participants acknowledge that the problem may involve additional complexities such as density variations and volume contraction, which are not fully resolved in the discussion.

LT72884
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ok, for the life of me i can not remember how to do the BASIC math for my issue. I mean, i can do calc but i have forgotten basic math haha.

here is my question. If i have 91% grain alcohol, how do i figure out how much water to add to it to drop the percentage to 70%. Dimensional analysis is i think what its called haha

thanks
 
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Is this by volume, v/v type? Assuming yes, then if volume of water to add is v, and ignoring dimensional analysis (although would be useful), and if you have Q amount of volume of your given 91% alcohol,

0.91/(Q+v)=0.71

Be aware, the question does not necessarily involve molarity.

Be aware, the question could involve densities or volume contraction changes for the different concentrations of alcohol in water.
 
symbolipoint said:
Is this by volume, v/v type? Assuming yes, then if volume of water to add is v, and ignoring dimensional analysis (although would be useful), and if you have Q amount of volume of your given 91% alcohol,

0.91/(Q+v)=0.71

Be aware, the question does not necessarily involve molarity.

Be aware, the question could involve densities or volume contraction changes for the different concentrations of alcohol in water.

EDIT: the above will work with grain alcohol, but what about rubbing alcohol?

thank you! I don't know why my brain does what it does. Literally, i can do integration by parts, or with partial fractions, then some one asks me to help them dilute rubbing alcohol and grain alcohol and i am like "umm, ill get back with you." its just a basic ratio. i was going to attack it with some ideas from thermodynamics class with density, specific gravity etc etc, but figured there is a easier ratio that i am not seeing..
 
LT72884 said:
EDIT: the above will work with grain alcohol, but what about rubbing alcohol?
Yes, of course. With jet fuel as well.
 
I was just asked to do this calculator yesterday. Originally I looked at it from a molality standpoint, but in the end ratio and proportions was much easier.
 
I was just asked to do this calculator calculation yesterday. Originally I looked at it from a molality standpoint, but in the end ratio and proportions was much easier.
If you look again at your original question, not a hint of moles came as part of the description or the question. All of it was concentration according to percents. If you try to put focus on moles or molarity OR molality when none is indicated, you simply make your question unnecessarily complicated. Sometimes, MOLALITY is involved in colligative properties, but again your question seems to not be of this kind.
 
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