Basic Proof Writing: Prove Sum of 3 Odd Ints is Odd

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Homework Help Overview

The discussion revolves around proving that the sum of three odd integers is odd, a topic within basic proof writing in mathematics. Participants are examining the formalism and notation used in the proof process.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are discussing the structure and clarity of the proof, with suggestions to simplify notation and formalism. There are questions about the necessity of certain mathematical expressions and whether the proof could be made more straightforward.

Discussion Status

The conversation is ongoing, with participants providing feedback on each other's proofs and notation. Some guidance has been offered regarding the reduction of formalism in the statements, and there is an openness to further questions on the topic.

Contextual Notes

Participants are considering the balance between formal mathematical language and clarity in communication. There is also a discussion about whether to create new threads for each question or to consolidate inquiries within a single thread.

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Homework Statement


Given a series of mathematical statements, some of which are true and some of which are false. Prove those of which are true, and disprove those which are false.
1. The sum of three odd integers is odd.
Text: Principles of Mathematics by Allendoefer and Oakley.

Homework Equations


x(px→qx)↔P⊆Q
Law of Detachment and Law of Substitution.

The Attempt at a Solution


I am mainly looking for feedback on my notation (formalism). What is the proper way of writing out a proper basic proof?
Statement: The sum of three odd integers is odd.
x(integers): If x is odd, then ∑3i=1xi is odd.
(1) Assume x1, x2, and x3 is odd. [Hypothesis]
(2) The integers a, b, and c exist such that x1=2a+1, x2=2b+1, and x3=2c+1. [Defn of odd]
(3) ∑3i=1xi =(2a+1)+(2b+1)+(2c+1)
=2a+1+2b+1+2c+1
=2a+2b+2c+2+1
=2(a+b+c+1)+1
=2(m)+1[Let m=a+b+c+1]
Therefore the sum of three odd integers is odd by definition.
 
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Keen94 said:

Homework Statement


Given a series of mathematical statements, some of which are true and some of which are false. Prove those of which are true, and disprove those which are false.
1. The sum of three odd integers is odd.
Text: Principles of Mathematics by Allendoefer and Oakley.

Homework Equations


x(px→qx)↔P⊆Q
Law of Detachment and Law of Substitution.

The Attempt at a Solution


I am mainly looking for feedback on my notation (formalism). What is the proper way of writing out a proper basic proof?
Statement: The sum of three odd integers is odd.
x(integers): If x is odd, then ∑3i=1xi is odd.
Not wrong, but writing ##\sum_{i = 1}^3 x_i## seems like overkill here. Just let x, y, and z be the odd integers. Their sum is x + y + z.

Keen94 said:
(1) Assume x1, x2, and x3 is odd. [Hypothesis]
(2) The integers a, b, and c exist such that x1=2a+1, x2=2b+1, and x3=2c+1. [Defn of odd]
(3) ∑3i=1xi =(2a+1)+(2b+1)+(2c+1)
=2a+1+2b+1+2c+1
=2a+2b+2c+2+1
=2(a+b+c+1)+1
=2(m)+1[Let m=a+b+c+1]
Therefore the sum of three odd integers is odd by definition.
The gist of your proof is fine, but you're using something that is in my opinion unnecessary (the summation and subscripted variables).
 
Thank for replying Mark44 and taking the time to help me. Would the following adjustment make the proof less overkill?

Statement: The sum of three odd integers is odd.
xyz(integers): If x, y, and z are odd, then x+y+z is odd.
(1) Assume x, y, and z are odd [Hypothesis]
(2) The integers a, b, and c exist such that x=2a+1, y=2b+1, and z=2c+1. [Defn of odd]
(3) x+y+z =(2a+1)+(2b+1)+(2c+1)
=2a+1+2b+1+2c+1
= 2a+2b+2c+2+1
=2(a+b+c+1)+1
=2(m)+1 [Defn of odd]
Therefore x+y+z is odd by definition of odd.
 
That looks good. The only think I would add is that it wouldn't hurt (IMO) to reduce the formalism a bit more in your statement of the problem. Instead of saying "∀x∀y∀z(integers): If x, y, and z are odd, then x+y+z is odd," you could say the same thing as "For any integers x, y, and z, x + y + z is odd." All the rest looks fine.
 
Mark44 said:
That looks good. The only think I would add is that it wouldn't hurt (IMO) to reduce the formalism a bit more in your statement of the problem. Instead of saying "∀x∀y∀z(integers): If x, y, and z are odd, then x+y+z is odd," you could say the same thing as "For any integers x, y, and z, x + y + z is odd." All the rest looks fine.
Thanks for the feed back Mark44. Going forward I will have more questions about this topic. Should I keep creating new threads, as in a new thread per question or just keep everything under one thread? Thanks.
 
Keen94 said:
Thanks for the feed back Mark44. Going forward I will have more questions about this topic. Should I keep creating new threads, as in a new thread per question or just keep everything under one thread? Thanks.
New question -- new thread.
 
Gotcha, see you there haha.
 

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