- #1

RJLiberator

Gold Member

- 1,095

- 63

Member warned about posting without the template

Determine the singular points of each function:

f(z) = (z^3+i)/(z^2-3z+2)

So it is my understanding that a singular point is one that makes the denominator 0 in this case.

We see that (z-2)(z-1) is the denominator and we thus conclude that z =2, z=1 are singular points.

f(z) = (2z+1)/(z(z^2+1))

So, z=0, +/- i are singular points.

Am I understanding this correctly?

f(z) = (z^3+i)/(z^2-3z+2)

So it is my understanding that a singular point is one that makes the denominator 0 in this case.

We see that (z-2)(z-1) is the denominator and we thus conclude that z =2, z=1 are singular points.

f(z) = (2z+1)/(z(z^2+1))

So, z=0, +/- i are singular points.

Am I understanding this correctly?