Basic S.T.R. problem. K vs K' systems.

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SUMMARY

The discussion centers on the transformation of coordinates between two reference frames, K and K', in the context of special relativity. An event occurs in system K' at coordinates (2 m, 3.5 m, 3.5 m, 0) while K' moves at a speed of 0.92c along the x-axis of system K. The relevant equations for Lorentz transformation are provided: x' = γ(x - vt) and t' = γ(t - (v/c²)x). The confusion arises regarding the time coordinate t in system K, which is not necessarily zero even when t' is zero.

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Homework Statement




An event occurs in system K' at x' = 2 m, y' = 3.5 m, z' = 3.5 m, and t' = 0. System K' and K have their axes coincident at t = t' = 0, and system K' travels along the x-axis of system K with a speed 0.92c. What are the coordinates of the event in system K?


Homework Equations



x' = [tex]\gamma[/tex](x-vt)
t' = [tex]\gamma[/tex](t-(v/c^2)x)

The Attempt at a Solution



I know that, as the system is not moving in either the y or z directions that y and z are the same, so y=3.5m and z=3.5m. I feel as though t should = 0, because in the problem statement it clearly says that "their axes coincident at t=t'=0 so if t'=0 then t should =0, but I've been told that's not right... I'm completely at a loss for x.
 
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What that means is (t,x)=(0,0) and (t',x')=(0,0) are the same point. It doesn't say anything about points other than the origin. It's like rotations of the xy-plane. The origin for both the unrotated and rotate axes coincide, but other points on the x-axis don't lie on the x' axis. Similarly, just because a point lies on the t'=0 line, it's not going to be on the t=0 line.
 

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