Batter hits a ball momentum problem

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The discussion focuses on calculating the impulse delivered to a baseball by a batter's swing and the subsequent velocity of the baseball after impact. The force exerted by the batter is given by F(t)=(13000N)sin(1.05ms^-1) over a duration of 3.00ms, resulting in an impulse of 24.8N. The baseball, with a mass of 300.0g and an initial velocity of 35.0m/s, leaves the bat at a final velocity of 47.5m/s. The collision is identified as elastic, where momentum is conserved.

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A batter hits a ball with a force of F(t)=(13000N)sin(1.05ms^-1) for 3.00ms. A baseball is thrown so it has a velocity of 35.0m/s toward the batter just before it hits the bat. Assuming the baseball has a mass of 300.0g calculate:

a. the impulse delivered to the ball over the 3.00ms

b.the velocity of the baseball just after it leaves the bat

I really don't know where to start. The answers are impulse=24.8N and 47.5m/s

Any help would be great!
 
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I'd start with the equations, and identifying what type of collision it is. Would you call this collision elastic, inelastic, or perfectly inelastic?
 


i would say its elastic, what equations are you talking about?
 


F(t)=(13000N)sin(1.05ms^-1)

i don't understand. sin is a function for angles, how can you deduce "sin 1.05ms-1"

impulse=24.8N

impulse is basically change in momentum. so the unit is kg ms-1 not N
 


m1v1=m2v2

impulse=F*change in time
 

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