A batter hits a baseball motion and velocity problem

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SUMMARY

A batter hits a baseball at a speed of 35 m/s and an angle of 65 degrees, resulting in a flight time of 6.47 seconds and a total distance of 95.69 meters. The outfielder, starting 70 meters away, must cover a distance of 25.69 meters to catch the ball. To determine the required speed, the outfielder must run this distance within the calculated time of 6.47 seconds, leading to a necessary running speed of approximately 3.97 m/s.

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  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Basic knowledge of trigonometry
  • Ability to perform unit conversions and calculations
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  • Calculate the outfielder's required speed using the formula: speed = distance/time
  • Explore the effects of air resistance on projectile motion
  • Study advanced projectile motion scenarios involving varying angles and speeds
  • Learn about real-world applications of projectile motion in sports physics
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Students studying physics, sports coaches analyzing player performance, and anyone interested in the mechanics of projectile motion in sports contexts.

kirby27
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A batter hits a baseball at a speed of 35 m/s?
and an angle of 65 degrees above the horizontal. At the same instant, an outfielder 70 m away begins running away form the batter in the line of the ball's flight, hoping to catch it. How fast must he outfielder run to catch the ball? ignore air resistance, and assume the fielder catches the ball at the same height at which it left that bat.

i used the formula y = (Vo*sin(theta))t - (1/2)gt^2 and found t = 6.47 s
using Xf=Xo + Voxt i found Xf = 95.69m. this is the distance of the bal's flight. therefore the fiedier must run 95.69 - 70 = 25.69 meters to the ball. and i am stuck after this.
 
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kirby27 said:
A batter hits a baseball at a speed of 35 m/s?
and an angle of 65 degrees above the horizontal. At the same instant, an outfielder 70 m away begins running away form the batter in the line of the ball's flight, hoping to catch it. How fast must he outfielder run to catch the ball? ignore air resistance, and assume the fielder catches the ball at the same height at which it left that bat.

i used the formula y = (Vo*sin(theta))t - (1/2)gt^2 and found t = 6.47 s
using Xf=Xo + Voxt i found Xf = 95.69m. this is the distance of the bal's flight. therefore the fiedier must run 95.69 - 70 = 25.69 meters to the ball. and i am stuck after this.

You have calculated how far away the fielder has to go, and also the time the ball will be there. From that you can work out how fast he needs to run!
 
dont give me TOO much advice
 

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