- #1

kirby27

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and an angle of 65 degrees above the horizontal. At the same instant, an outfielder 70 m away begins running away form the batter in the line of the ball's flight, hoping to catch it. How fast must he outfielder run to catch the ball? ignore air resistance, and assume the fielder catches the ball at the same height at which it left that bat.

i used the formula y = (Vo*sin(theta))t - (1/2)gt^2 and found t = 6.47 s

using Xf=Xo + Voxt i found Xf = 95.69m. this is the distance of the bal's flight. therefore the fiedier must run 95.69 - 70 = 25.69 meters to the ball. and i am stuck after this.