Calculating Impulse from a Bat to a Baseball: Finding Direction and Magnitude

  • Thread starter Thread starter frownifdown
  • Start date Start date
  • Tags Tags
    Baseball Impulse
Click For Summary

Homework Help Overview

The discussion revolves around calculating the impulse delivered to a baseball by a bat, focusing on both the direction and magnitude of the impulse. The problem involves concepts from mechanics, specifically momentum and impulse, as the baseball transitions from horizontal motion to vertical motion after impact.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of initial and final momentum, with some questioning whether the initial momentum should be considered as zero or the calculated value. There are attempts to apply vector addition and subtraction to find the impulse, with confusion arising around the use of trigonometric functions for angle determination.

Discussion Status

Participants are actively engaging with the problem, exploring different methods for calculating the angle and magnitude of the impulse. Some guidance has been offered regarding the use of the atan2 function for angle calculation, and there is recognition of the need to consider the quadrant of the angle. However, there is no explicit consensus on the correct approach or solution yet.

Contextual Notes

There is mention of potential confusion regarding the signs of momentum components and the need for clarity on the quadrant in which the angle lies. Participants express frustration over the problem's complexity and the accuracy of their calculations.

frownifdown
Messages
72
Reaction score
0
A 0.14 kg baseball moves horizontally with a speed of 29 m/s toward a bat. After striking the bat the ball moves vertically upward with 46% of its initial speed. Find the direction and magnitude of the impulse delivered to the ball by the bat.

Find the ° (measured from the initial direction of the ball)
Find the kg·m/s




J = ΔP, Pf=Pi, P=mv



I have the initial momentum as 4.06 kgm/s, and that is just the momentum of the baseball. Or would I put initial momentum as 0? I think it would be the 4.06 because at the beginning of the problem the baseball is moving. The momentum of the baseball after the hit is 1.86 kgm/s, which I got by multiplying the 46% by the mass of the baseball, giving me 13.34 m/s and then multiplying that by .14kg giving me 1.86 kgm/s. I'm unsure how to proceed from here.
 
Physics news on Phys.org
Impulse J is the change in momentum (mv_final - mv_initial). You have to vectorially subtract them. Familiar with vector addition and subtraction?
 
PhanthomJay said:
Impulse J is the change in momentum (mv_final - mv_initial). You have to vectorially subtract them. Familiar with vector addition and subtraction?

Yupp. So I put the x vector as 29 and the y vector as 13.34 which gave me a hypotenuse of 31.92, then I figured out theta to be 24.7 by doing the arc tangent of 13.34/29 which I put as the direction of the impulse but it is telling me that it is wrong. What did I screw up?
 
Make a sketch and determine which quadrant the angle should be in. arctan is insensitive to the placement of signs in its argument (it can't tell if a negative argument came from the numerator or denominator of the values comprising the argument). A better function is the atan2 function which takes two arguments, the y and the x (or the "rise" and the "run"), and always returns an unambiguous result.
 
gneill said:
Make a sketch and determine which quadrant the angle should be in. arctan is insensitive to the placement of signs in its argument (it can't tell if a negative argument came from the numerator or denominator of the values comprising the argument). A better function is the atan2 function which takes two arguments, the y and the x (or the "rise" and the "run"), and always returns an unambiguous result.

So how would I put it in the calculator then?
 
You can use arctan, but you may have to adjust the result (generally involving a factor of 180 degrees). Make the sketch. Determine which angle you obtained. Adjust if required.

Why don't you play with a few examples and see how your arctan function behaves? Choose some x and y values from each quadrant and see what arctan returns.

Alternatively, if your calculator has built-in polar to rectangular and rectangular to polar conversions, use that.
 
You are determining the magnitude of the velocity change when the problem asks for the magnitude of the impulse. Angle direction looks ok with respect to the initial direction of the thrown ball but you should round it off to 2 significant figures.
 
PhanthomJay said:
You are determining the magnitude of the velocity change when the problem asks for the magnitude of the impulse. Angle direction looks ok with respect to the initial direction of the thrown ball but you should round it off to 2 significant figures.

So round it off to 25? Still wrong, and good point on the impulse. I'll try to work that out.
 
Supposing the initial momentum is directed along the +x axis, and the final momentum directed along the +y axis, then:

attachment.php?attachmentid=64097&stc=1&d=1384900419.gif
 

Attachments

  • Fig1.gif
    Fig1.gif
    869 bytes · Views: 896
  • #10
gneill said:
Supposing the initial momentum is directed along the +x axis, and the final momentum directed along the +y axis, then:

attachment.php?attachmentid=64097&stc=1&d=1384900419.gif

I got 335 for that angle, but it's still wrong. This is the only problem on the assignment that I had any trouble with. Very frustrating
 
  • #11
What quadrant is the angle in? What is the range of angles for that quadrant?
 
  • #12
gneill said:
What quadrant is the angle in? What is the range of angles for that quadrant?

1st quadrant and 0-90
 
  • #13
frownifdown said:
1st quadrant and 0-90
Which quadrant?

attachment.php?attachmentid=64098&stc=1&d=1384902197.gif
 

Attachments

  • Fig2.gif
    Fig2.gif
    2.7 KB · Views: 904
  • #14
gneill said:
Which quadrant?

attachment.php?attachmentid=64098&stc=1&d=1384902197.gif

Oh for some reason I was thinking it was starting from the other side. I got it now, thank you so much!
 

Similar threads

Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 13 ·
Replies
13
Views
1K