Battery Problem (finding current w/ batteries in parallel)

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The discussion focuses on calculating the current through a 200-ohm resistor in a circuit with three batteries of different voltages connected in parallel. The user struggles to apply the loop rule effectively due to the complexity of having multiple unknowns and equations. It is suggested that they utilize one junction equation and three loop equations, and consider using a matrix to simplify calculations. After further analysis, the user finds the total current (I) to be 0.041 A, leading to a voltage drop (deltaV) of 8.1V across the resistor, while noting a different current when the batteries were connected in series. The conversation emphasizes the importance of correctly applying circuit analysis techniques to solve for unknowns.
aleksxxx
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Homework Statement


Find the current flowing through the 200ohm resistor
physics2.jpg


E1=5v
E2=10v
E3=15v
r1=3ohms
r2=6ohms
r3=9ohms

The Attempt at a Solution



I know that I1+I2+I3=I
I can't seem to get a loop rule that will allow me to solve for I though.

I came up with the equivalent resistance in the three resistors equal to 1.6ohms.

I tried to draw a simplified circuit diagram, but i am not sure how to do that with different voltages on batteries in parallel.

thanks
 
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Equivalent resistance won't help. Youve got 4 unknowns and need 4 equations. Theres enough information to use one junction equation and 3 loops. Make use of the inner loops, and use a matrix to avoid algebra mistakes whenever possible
 
turdferguson said:
Equivalent resistance won't help. Youve got 4 unknowns and need 4 equations. Theres enough information to use one junction equation and 3 loops. Make use of the inner loops, and use a matrix to avoid algebra mistakes whenever possible

i tried that and i seem to just keep proving that I2=I2, I1=I1, etc...
 
http://www.bluebit.gr/matrix-calculator/linear_equations.aspx

Plug your equations into this matrix calculator to see if youre missing a necessary loop or if youre just hung up on how to reach the solution
 
I worked on the loop equations more and found I1, I2, and I3 in terms of I.

I then substituted those into the I1+I2+I3=I equation getting a current (I) of .041 A leading to a deltaV of 8.1V.

Does this sound right? The Current was .137A when connected in series and the deltaV of the 200 ohm resistor was 27.4V.

Thanks
 
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