1. The problem statement, all variables and given/known data A battery with voltage V=12V is connected to the primary of a transformer. A resistor with resistance R =20 Ohms is connected to the transformer secondary. The transformer has an iron core with Np=200 turns on the primary and Ns=600 turns on the secondary. Assume the resistance of the wires is zero. What is Is, the current in the resistor? 2. Relevant equations Vs= (Ns/Np)Vp V=IR 3. The attempt at a solution Vs=(600/200) * 12 V Vs=36 V V=IR 36V=I(20 ohms) I =1.8A, but the answer is 0? Could someone please show me where I have made my error or how to arrive at the answer of 0 A?