(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A battery with voltage V=12V is connected to the primary of a transformer. A resistor with resistance R =20 Ohms is connected to the transformer secondary. The transformer has an iron core with Np=200 turns on the primary and Ns=600 turns on the secondary. Assume the resistance of the wires is zero.

What is Is, the current in the resistor?

2. Relevant equations

Vs= (Ns/Np)Vp

V=IR

3. The attempt at a solution

Vs=(600/200) * 12 V

Vs=36 V

V=IR

36V=I(20 ohms)

I =1.8A, but the answer is 0? Could someone please show me where I have made my error or how to arrive at the answer of 0 A?

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# Battery with voltage V=12V is connected to the primary of a transform

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