- #1

Ananthan9470

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But shouldn't the speed at the end be independent of the shape of the wire? The potential energy of the bead at the start is ##U = mgh## and the final kinetic energy is ##\frac{1}{2} m v^2##

equating these you get, ##v = \sqrt{2gh}##. and that simply depends on ##h## and nothing else.

Is this wrong?