Beat FrequencyWhat is the new tension in the string that slipped?

[r_swayze]

Two identical strings are sounding the same fundamental tone of frequency 156 Hz. Each string is under 228 N of tension. The peg holding one string suddenly slips, reducing its tension slightly, and the two tones now create a beat frequency of three beats per second. What is the new tension in the string that slipped?

My attempt so far:

f_beat = f₁ - f₂ = 3Hz

f₁ = 156Hz

3Hz - 156Hz = -f₂

f₂ = 153Hz

So how do I find the tension for this frequency? Usually there is more information given such as the linear density or speed of the wave. I don't see how I can find the tension without those variables. Any help?

 

[rl.bhat]

For identical strings frequency f = k*(T)^1.2, where k is constant and T is the tension in the string. So
f1/f2 = (T1/T2)^1/2.
You have already found f1 and f2. T1 is given. Find T2.