Beginner having trouble taking derivative

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SUMMARY

The discussion centers on the application of the chain rule and product rule in calculus, specifically for the function g(x) = (1 + 4x)⁵(3 + x - x²)⁸. The user understands both rules individually but struggles to combine them effectively. The derivative g'(x) is expressed as g'(x) = f(x)h'(x) + f'(x)h(x), where f(x) = (1 + 4x)⁵ and h(x) = (3 + x - x²)⁸. The key takeaway is that the product rule must be applied first, followed by the chain rule for each derivative involved.

PREREQUISITES
  • Understanding of the Product Rule for Differentiation
  • Understanding of the Chain Rule for Differentiation
  • Basic knowledge of polynomial functions
  • Familiarity with function notation and derivatives
NEXT STEPS
  • Practice combining the Product Rule and Chain Rule with various functions
  • Study examples of derivatives involving multiple rules
  • Explore advanced differentiation techniques, such as implicit differentiation
  • Learn about higher-order derivatives and their applications
USEFUL FOR

Students studying calculus, educators teaching differentiation techniques, and anyone looking to strengthen their understanding of combining differentiation rules.

Heinz21
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Hello, i am having trouble taking the derivative of functions with using the chain rule plus another rule such as the product rule... i know how to do chain rule by it self and product rule by itself but i am having trouble using them together.. here is an example
g(x)= ( 1+4x )5 ( 3+x-x2 )8
 
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Let f(x)=(1+4x)5 and h(x)=(3+x-x2)8

The g(x)=f(x)h(x) and g'(x)=f(x)h'(x) + f'(x)h(x)

Can you do the rest yourself?
 
What Mathman is saying is that you first must use The Product Rule for Differentiation.
Then each derivative [h ' (x) and f ' (x) ] will require using The Chain Rule.
 
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