Do Bernoulli Numbers Always Have Unique Prime Factors in Their Denominators?

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The discussion centers on whether the denominators of Bernoulli numbers, when expressed as irreducible fractions, contain unique prime factors. It references a known result by Ramanujan, which states that the primes 2 and 3 appear exactly once in the denominators. However, the original poster questions if this uniqueness extends to all prime factors in the denominators. Examples of specific Bernoulli numbers illustrate the denominators' prime factorizations. Additional insights or confirmations regarding this conjecture are encouraged.
Damidami
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Is this a known bernoulli number conjeture/theorem?:
The denominators of B_n (when expressed as an irreducible fraction), doesn't contain as a factor powers of prime numbers (ex. isn't divided by 5^2)

Example:

B_2 = 1/6
6 = 2*3

B_4 = -1/30
30 = 2*3*5

B_{24} = -236364091/2730
2730 = 2*3*5*7*13

I know Ramanujan proved that the denominator contain 2 and 3 as a factor one and only once, but I hadn't heard that any prime on the factorization of the denominator happens only once.
 
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Nevermind.

http://en.wikipedia.org/wiki/Von_Staudt%E2%80%93Clausen_theorem"

Aditional information is welcome.
 
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