Bessel Function, Orthogonality and More

Post
Messages
3
Reaction score
0
Hello,
I'm trying to show that

Integral[x*J0(a*x)*J0(a*x), from 0 to 1] = 1/2 * J1(a)^2

Here, (both) a's are the same and they are a root of J0(x). I.e., J0(a) = 0.

I have found and can do the case where you have two different roots, a and b, and the integral evaluates to zero (orthogonality). How do I go about showing this relationship? I can't find details anywhere.
 
Physics news on Phys.org
Try expanding J0 in a power series, collect terms in like powers, and integrate. Then you can also expand the right side in a power series and show the two are equal.
 
Hi,
Sorry for my ignorance, but if expanding into a power series don't we have two infinite sums multiplied together? I attempted it but wasn't able to get anywhere nicely (maybe it's beyond me)

I was thinking something more along the lines of this:
http://physics.ucsc.edu/~peter/116C/bess_orthog.pdf
but I don't see the proper modifications that will give me my identity.

Any further hints would be amazing!
 
Why isn't equation 15 of the link you sent exactly what you are looking for?
 
Thread 'Direction Fields and Isoclines'
I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...

Similar threads

Back
Top