- #1
FQVBSina_Jesse
- 54
- 9
- TL;DR
- Bessel's integral form: is it e to the power of a cosine or sine?
Hello all,
This is knowledge needed to solve my take-home final exam but I just want to ask about the definition of Bessel's integrals. This is not a problem on the exam. Wikipedia says the integral is defined as:
$$J_n(x) = \frac {1} {2\pi} \int_{-\pi}^{\pi} e^{i(xsin(\theta) - n\theta)} \, d\theta$$
My professor wrote it as:
$$J_m(Z) = \frac {1} {2\pi} \int_{-\pi}^{\pi} e^{i(Zcos(\theta))} e^{(- im\theta)} \, d\theta$$
Ignoring notation differences and I understand that cosine and sine form an orthogonal basis and are essentially the same as they can be easily expressed in terms of each other, but how do I justify that these two expressions are EXACTLY the same without any modifications with negative signs and such?
Thanks!
Jesse
This is knowledge needed to solve my take-home final exam but I just want to ask about the definition of Bessel's integrals. This is not a problem on the exam. Wikipedia says the integral is defined as:
$$J_n(x) = \frac {1} {2\pi} \int_{-\pi}^{\pi} e^{i(xsin(\theta) - n\theta)} \, d\theta$$
My professor wrote it as:
$$J_m(Z) = \frac {1} {2\pi} \int_{-\pi}^{\pi} e^{i(Zcos(\theta))} e^{(- im\theta)} \, d\theta$$
Ignoring notation differences and I understand that cosine and sine form an orthogonal basis and are essentially the same as they can be easily expressed in terms of each other, but how do I justify that these two expressions are EXACTLY the same without any modifications with negative signs and such?
Thanks!
Jesse