Beta Decay: 14C6 → 14N7+ e− + νe

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SUMMARY

Beta decay involves the transformation of a neutron into a proton and an electron, resulting in the emission of a beta particle (not a gamma ray) and an antineutrino, as illustrated by the equation 14C6 → 14N7 + e− + νe. This process increases the atomic number while maintaining the same mass number, leading to the formation of a positively charged ion due to the loss of an electron. Contrary to the assumption that ions are inherently unstable, many ions exist stably in nature.

PREREQUISITES
  • Understanding of beta decay and nuclear reactions
  • Familiarity with atomic structure and ionization
  • Knowledge of particle physics terminology, specifically beta particles and gamma rays
  • Basic grasp of nuclear equations and their implications
NEXT STEPS
  • Study the principles of nuclear decay processes, focusing on beta decay
  • Learn about the stability of ions and their role in chemical reactions
  • Explore the differences between beta particles and gamma rays in particle physics
  • Investigate the applications of beta decay in radiocarbon dating and nuclear medicine
USEFUL FOR

Students of nuclear physics, educators teaching atomic structure, and professionals in fields related to radiochemistry and nuclear medicine will benefit from this discussion.

Crystal037
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Homework Statement
In beta-decay, a gamma ray that is a fast moving electron is emitted due to the conversion of a neutron to a proton and an electron to increase the stability. As a result, the atomic number increases while the mass number remains the same. But when the atomic no. increases as an extra proton is added, won't the atom need the electron it emits to stabilise the atom which by now has a positive charge
Relevant Equations
Eg: 14C6 → 14N7+ e− + νe
Problem Statement: In beta-decay, a gamma ray that is a fast moving electron is emitted due to the conversion of a neutron to a proton and an electron to increase the stability. As a result, the atomic number increases while the mass number remains the same. But when the atomic no. increases as an extra proton is added, won't the atom need the electron it emits to stabilise the atom which by now has a positive charge
Relevant Equations: Eg: 14C6 → 14N7+ e− + νe

According to me, The atom as its electron has been shot out would have a positive charge.
 
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Crystal037 said:
Problem Statement: In beta-decay, a gamma ray that is a fast moving electron is emitted due to the conversion of a neutron to a proton and an electron to increase the stability. As a result, the atomic number increases while the mass number remains the same. But when the atomic no. increases as an extra proton is added, won't the atom need the electron it emits to stabilise the atom which by now has a positive charge
Relevant Equations: Eg: 14C6 → 14N7+ e− + νe

The atom as its electron has been shot out would have a positive charge.
Yes, this is called an ion.

Note that a beta particle is not a gamma ray.
 
Then how does the ion gets an electron to stabilize itself
 
What makes you think ions are necessarily unstable? The world is full of ions.
 

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