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Kim_Jong
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- Homework Statement
- Consider a nuclear process in which U-238 undergoes several Alpha and Beta decays and becomes Pb-206. How many Alpha and Beta decays occur in this process?
- Relevant Equations
- .
Alpha particle has two protons and neutrons so mass = 4.
4x = 238 -206.
x = 1/4(238-206) = 8 Alpha decays.
How would I determine the number of Beta decays? Since the mass doesn't change here.
4x = 238 -206.
x = 1/4(238-206) = 8 Alpha decays.
How would I determine the number of Beta decays? Since the mass doesn't change here.
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