Billiard ball collision at right angle

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SUMMARY

The discussion centers on the elastic collision of two billiard balls of equal mass moving at right angles. Ball A travels upward along the y-axis at 2.0 m/s, while Ball B moves right along the x-axis at 3.7 m/s. Post-collision, Ball B moves along the positive y-axis, necessitating the calculation of Ball A's final direction and speeds. The conservation of momentum and kinetic energy principles are applied to solve for the final velocities of both balls.

PREREQUISITES
  • Understanding of elastic collisions
  • Familiarity with momentum conservation principles
  • Knowledge of kinetic energy conservation
  • Basic proficiency in vector analysis
NEXT STEPS
  • Study the conservation of momentum in two dimensions
  • Learn how to apply the equations for elastic collisions
  • Explore vector decomposition in physics problems
  • Investigate real-world applications of elastic collisions in sports
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of elastic collisions in two-dimensional motion.

Brite
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Homework Statement


Two billiard balls of equal mass move at right angles and meet at the origin of an xy coordinate system. Ball A is moving upward along the y-axis at 2.0 m/s and ball B is moving to the right along the x-axis with speed 3.7 m/s. After the collision (elastic), ball B is moving along the positive y axis. What is the final direction of ball A and what are their two speeds?

Homework Equations


mAvA + mBvB = mav'A + mBv'B
1/2mAvA2 + 1/2mBvB2 = 1/2mAv'A2 + 1/2mBv'B2

The Attempt at a Solution


I know that because this is an elastic collision, momentum and kinetic energy are conserved. I think it's just that the two balls start on different axes is what's throwing me off.
 
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Brite said:

Homework Statement


Two billiard balls of equal mass move at right angles and meet at the origin of an xy coordinate system. Ball A is moving upward along the y-axis at 2.0 m/s and ball B is moving to the right along the x-axis with speed 3.7 m/s. After the collision (elastic), ball B is moving along the positive y axis. What is the final direction of ball A and what are their two speeds?


Homework Equations


mAvA + mBvB = mav'A + mBv'B
1/2mAvA2 + 1/2mBvB2 = 1/2mAv'A2 + 1/2mBv'B2


The Attempt at a Solution


I know that because this is an elastic collision, momentum and kinetic energy are conserved. I think it's just that the two balls start on different axes is what's throwing me off.

Welcome to PF.

Indeed the 2 dimensions do make a difference. You will want to treat them separately.

Momentum in x is conserved
Momentum in y is conserved
KE is conserved.
 

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