Elastic collision - Trigonometry equations

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Homework Help Overview

The discussion revolves around an elastic collision problem involving billiard balls, where one ball is initially in motion and collides with a stationary identical ball. Participants are tasked with determining the final speed and direction of both balls post-collision, utilizing principles of conservation of energy and momentum.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the use of trigonometric identities to simplify the equations related to the angles involved in the collision. There is mention of forming equations based on momentum conservation and manipulating them to isolate variables.

Discussion Status

Some participants have offered guidance on how to approach the problem by suggesting the use of trigonometric identities and the cosine rule to relate the angles and speeds. There appears to be a collaborative effort to clarify the setup and explore various methods without reaching a definitive conclusion.

Contextual Notes

Participants are working within the constraints of the problem's setup, which includes specific initial conditions and the requirement to apply conservation laws. The complexity of the trigonometric relationships is acknowledged as a challenge in finding a solution.

Dandi Froind
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Homework Statement


A billiard ball moves at a speed of 4.00m/s and collides elastically with an identical stationary ball. As a result, the stationary ball flies away at a speed of 1.69m/s, as shown in Figure A2.12. Determine:
  1. the final speed and direction of the incoming ball after the collision.
  2. the direction of the stationary ball after the collision.

Homework Equations


Conservation of Energy and momentum:
E before = E after
Σpx=0
Σpy=0

The Attempt at a Solution


As you can see, I have 2 equations with 2 angles that I don't know.
However, I couldn't find the right way to solve it due to trigonometry complexity.
I am sure that taking into account the fact that (sin(theta))^2 +(cos(theta))^2 = 1 would help in some way.
https://image.ibb.co/gv6YVw/Capture.jpg
Capture.jpg
 

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Hi again,

As long as I can see, you use the right method. You are right, the equation sin2θ1+cos2θ1=1 can help you.

You must think how you can form this (sin2θ1+cos2θ1). Try to "play" with these two equations. (Hint: You will end up solving an equation with only one of the two angles firstly).
 
Dandi Froind said:

Homework Statement


A billiard ball moves at a speed of 4.00m/s and collides elastically with an identical stationary ball. As a result, the stationary ball flies away at a speed of 1.69m/s, as shown in Figure A2.12. Determine:
  1. the final speed and direction of the incoming ball after the collision.
  2. the direction of the stationary ball after the collision.

Homework Equations


Conservation of Energy and momentum:
E before = E after
Σpx=0
Σpy=0

The Attempt at a Solution


As you can see, I have 2 equations with 2 angles that I don't know.
However, I couldn't find the right way to solve it due to trigonometry complexity.
I am sure that taking into account the fact that (sin(theta))^2 +(cos(theta))^2 = 1 would help in some way.
Yes, it would, Arrange the momentum equations in the form sin(θ2)=... cos(θ2)=...
Square them and add.
 
Thank you very much.
It was very helpful.
 
Dandi Froind said:

Homework Statement


A billiard ball moves at a speed of 4.00m/s and collides elastically with an identical stationary ball. As a result, the stationary ball flies away at a speed of 1.69m/s, as shown in Figure A2.12. Determine:
  1. the final speed and direction of the incoming ball after the collision.
  2. the direction of the stationary ball after the collision.

Homework Equations


Conservation of Energy and momentum:
E before = E after
Σpx=0
Σpy=0

The Attempt at a Solution


As you can see, I have 2 equations with 2 angles that I don't know.
However, I couldn't find the right way to solve it due to trigonometry complexity.
I am sure that taking into account the fact that (sin(theta))^2 +(cos(theta))^2 = 1 would help in some way.
https://image.ibb.co/gv6YVw/Capture.jpg
View attachment 214226

If you take the two resultant momentum vectors after the collision and add them (i.e. put them tip to tail with each other), then, by conservation of momentum, you have the initial momentum vector.

This gives you a triangle where you know the lengths of all three sides. You could, therefore, use the cosine rule to get a simpler equation for each angle separately.

You could try this technique, as I find it a simpler method for collision problems.
 

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