Binomial Distribution: Calc Prob of 0, 1, 2 Defectives & Cost Estimate

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Homework Help Overview

The discussion revolves around a problem involving the binomial distribution, specifically calculating the probabilities of finding 0, 1, or 2 defective electronic components in a sample of 20, given that 5% of components are defective. The context also includes determining the expected cost of inspecting samples based on the acceptance criteria for the day's output.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the parameters of the binomial distribution, including the total number of trials (N=20) and the probability of defectiveness (5%). Questions arise about how to calculate the probabilities for 0, 1, and 2 defectives, with some expressing confusion about the binomial distribution itself.

Discussion Status

Some participants have provided links to resources that describe the binomial distribution and its calculations. Others are seeking step-by-step guidance on how to approach the problem, indicating a mix of understanding and uncertainty about the application of the binomial formula.

Contextual Notes

There is a noted lack of clarity among participants regarding the binomial distribution, with some expressing difficulty in grasping the concepts despite available resources. The problem's requirements for acceptance or rejection of the day's output based on the number of defectives are also under consideration.

markhboi
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can anyone help with this:

A particular type of electronic component for use in PCs is mass produced and subject to quality control checks since it is known that 5% of all components produced in this way are defective. The quality of a day's output is monitored as follows. A sample of 20 components is drawn from the day's output (which may be assumed to be large) and inspected for defective components. If this sample contains 0 or 1 defectives the day's output is accepted, otherwise it is rejected. If it contains more than 2 defectives the output is rejected. If the sample contains 2 defective a second sample of 20 is taken. If this sample contains 0 defectives the output is accepted, otherwise it is rejected.

Use the binomial distribution to calculate the probability of

(i) 0
(ii) 1
(iii) 2

defectives in a sample of 20.

Hence calculate the probability that the day's output is accepted.

Suppose that it is estimated that it costs £200 to inspect a sample of size 20. What is the expected cost of a day's sampling?
 
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Go through the first part of the problem first. You know N=20. Then try n=0, 1, and 2 using what you know about calculating probabilities using binomial distribution.
It states 5% of all components are defective. So how many in a sample of 20 are defective? What is the probabilities of having 0 defectives? How about 1 and 2?
Here is a link in case: http://mathworld.wolfram.com/BinomialDistribution.html
 
thats the problem, i have no clue how to do binomial and when ever i look at it online it just blags my head, anyone help me with some step by step instructions on working it out?
 
Here is a link: http://www.intmath.com/Counting-probability/12_Binomial-probability-distributions.php
It gives a description of the formula and examples, complete with solutions.

Once you have read through the page, move on to your question. It is a lot like the problems on the page. The important step is to identify the variables. Try (i) - the probably of 0 being the number of defective samples. Thus x=0. You are taking 20 total samples, so n=20. You are also given the probability that 5% are defective. Now it is a matter of plugging everything in the formula.
 
Last edited:
Moderator's note: thread moved from "Set Theory, Logic, Probability, Statistics"
 

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