- #1

- 3

- 0

A lot of 250 items that contains 15 defective items is subject to an acceptance sampling plan that calls for a smple of size 6 to be drawn(without replacement). the lot is accepted if the sample contains, at most, one defective item. find the probability that the lot is accepted.

The way I thought to do it was:

total number of samples that would be able to pass/total number of sample possible = (250-14)C6 / 250C6.

A friend of mine said that it should be done like this: (6c0) * 0.06^0 * (0.94)^6 + 6c1 * (0.06^1) * (0.94)^5, and something about it being a binomial distribution, but I don't know why/what he's saying.

Any help would be greatly appreciated.