Binomial Expansion Part I: Find Formula for 8th Power - 65 chars

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    Binomial Expansion
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The discussion focuses on the binomial expansion of various expressions raised to the 8th power, specifically (x + y), (w + z), (x - y), and (2a + 3b). Participants detail how to derive the expansions and substitute values for x and y in each case. The key takeaway is that the expansion of (x + y)^8 can be utilized to find the expansions of the other expressions by appropriately substituting values for x and y. The discussion emphasizes the importance of correctly applying powers during substitution.

PREREQUISITES
  • Understanding of binomial expansion
  • Familiarity with binomial coefficients
  • Knowledge of algebraic substitution
  • Basic skills in polynomial manipulation
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  • Study the binomial theorem for higher powers
  • Learn about binomial coefficients and their applications
  • Explore polynomial substitution techniques
  • Investigate the implications of variable substitution in algebra
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Students, educators, and anyone interested in advanced algebra, particularly those studying binomial expansions and polynomial expressions.

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Part I. Write out the binomial expansion for each binomial raised to the 8th power.
1. (x + y) 2. (w + z) 3. (x - y) 4. (2a + 3b)
Part II. Now explain how your answer for #1 could be used as a formula to help you answer each of the other items. In each case, for #2, 3 and 4, tell what would x equal and what would y equal.

I did the binomial expansions. Those are easy, but how can you find the value?
 
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toyjoha said:
Part I. Write out the binomial expansion for each binomial raised to the 8th power.
1. (x + y) 2. (w + z) 3. (x - y) 4. (2a + 3b)
Part II. Now explain how your answer for #1 could be used as a formula to help you answer each of the other items. In each case, for #2, 3 and 4, tell what would x equal and what would y equal.

I did the binomial expansions. Those are easy, but how can you find the value?
http://lmgtfy.com/?q=binomial+coefficient
 
What did you get for the expansion of (x+y)^5? What happens when you substitute another term for x and y, say x=3c and y=2d into the expansion of (x+y)^5? Remember when you substitute you must pay close attention to apply any powers to the whole term, not just the variable. So if you see x^5 and you substitute x=3c, then the substituted expression would be (3c)^5, NOT 3(c^5).
 
toyjoha said:
Part I. Write out the binomial expansion for each binomial raised to the 8th power.
1. (x + y) 2. (w + z) 3. (x - y) 4. (2a + 3b)
Part II. Now explain how your answer for #1 could be used as a formula to help you answer each of the other items. In each case, for #2, 3 and 4, tell what would x equal and what would y equal.

I did the binomial expansions. Those are easy, but how can you find the value?
They are not asking for "values". To use your answer to (1) to get (2) let x= w and let y= z. Similarly for (3) x stays x but y becomes -y. Finally, for (4) let x= 2a, y= 3b.
 

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