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sinkersub
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Homework Statement
Find the Laurent Series of [itex] f(z) = \frac{1}{z(z-2)^3} [/itex] about the singularities z=0 and z=2 (separately).
Verify z=0 is a pole of order 1, and z=2 is a pole of order 3.
Find residue of f(z) at each pole.
Homework Equations
The solution starts by parentheses in the form (1 - az), where a is some constant.
[itex] f(z) = \frac{-1}{8z(1-\frac{z}{2})^3} [/itex]
The Attempt at a Solution
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The solution given expands [itex] \frac{1}{(1-\frac{z}{2})^3} [/itex] as follows, and I just don't understand how it does it! I'm simply trying to recognise what expansion this is, as I can see it's used later too! I understand almost all of the rest of the problem. A general series/hint to what series is used would be amazing!
[itex] = 1 + (-3)(\frac{-z}{2}) +\frac{(-3)(-4)(\frac{-z}{2})^2}{2!} + \frac{(-3)(-4)(-5)(\frac{-z}{2})^3}{3!} + ... [/itex]
I think it's a binomial expansion, but how does a binomial expansion work for negative powers?
Is it a binomial expansion?
sinkersub