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**1. Homework Statement**

A block of mass m1 is attached to the axle of a uniform solid cylinder of mass m2 and radius R by massless strings. The two accelerate down a slope that makes an angle [itex]\theta[/itex] with the horizontal. The cylinder rolls without slipping and the block slides with coefficient of kinetic friction [itex]\mu[/itex] between the block and slope. The strings are attached to the cylinders axle with frictionless loops so that the cylinder can roll freely without any torque from the string. Find an expression for the acceleration of the pair, assuming that the string remains taut.

**2. Homework Equations**

F=ma

T=tension in string

N=normal force

a=acceleration of system

**3. The Attempt at a Solution**

I applied Newton to the block and cylinder separately.

For the block (choosing axis with x direction parallel to the slope and y direction perpendicular to the slope)

y direction:

[tex]N-m_{1}g\cos\theta=0[/tex]

x direction:

[tex]T-\mu N + m_{1}g\sin\theta=m_{1}a[/tex]

For cylinder

x direction:

[tex]-T+m_{2}g\sin\theta = m_{2}a[/tex]

I can solve for the acceleration but its not in agreement with the answer in the book, so perhaps I am leaving something out. Could be the torque on the cylinder but not sure about that.

Anyone got any ideas?