Block moves down incline, hits spring, find spring constant

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SUMMARY

The discussion focuses on calculating the spring constant (K) for a block sliding down an incline and compressing a spring. The block, with a mass of 2 kg, compresses the spring by 0.03 m after sliding down a ramp inclined at 30 degrees. The energy conservation equation used is mgh = 0.5kx², where the gravitational potential energy is converted into spring potential energy. The key conclusion is that the maximum compression of the spring occurs when the block momentarily comes to rest, allowing for the calculation of K using the derived equation mg(L*sin θ) = 0.5k(Δx²).

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  • Familiarity with spring mechanics and Hooke's Law
  • Knowledge of trigonometric functions, specifically sine
  • Ability to manipulate algebraic equations for solving variables
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  • Calculate the spring constant K using the derived equation from the discussion
  • Explore energy conservation in different mechanical systems
  • Study the effects of varying angles on the potential energy of inclined planes
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2018-04-06.png

Homework Statement


[/B]
The block, initially at rest, slides down the ramp and compresses the spring 0.03 m.

Theta = 30 degrees
L = 1.25 m
M of block = 2 kg
Δx = 0.03 m

1) Write the expression for the initial and final energy states

2) Find the spring constant K

Homework Equations



mgh = 0.5kx2

The Attempt at a Solution



Can I say that when the block compresses the spring and comes to rest, h=0, in which case I wouldn't have to include mgh on the right hand side of the energy equation?

mg(L*sin theta) = 0.5*k*(x2) and solve for k...

This seems too easy, am I approaching this wrong?
 

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Looks good to me!
 
I would clarify. Is it saying it comes to rest at Δx, or is it saying that Δx is the maximum compression (more likely scenario)? What do you expect is going to happen from your real life experiences?

It appears you are saying, it "just" is at rest there (before it recoils), so kinetic energy is zero right at that point.
 
scottdave said:
Is it saying it comes to rest at Δx, or is it saying that Δx is the maximum compression (more likely scenario)?
While it never hurts to ask for clarification, the point of max compression is when it comes to rest (momentarily). That's what I assumed was being described.
 
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