(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A block of ice with mass 2.00kg slides 0.70m down an inclined plane that slopes downward at an angle of 30degrees below the horizontal. If the block of ice starts from rest, what is its final speed?

2. Relevant equations

W = 1/2(m)(v2)^2 - 1/2(m)(v1)^2

3. The attempt at a solution

W = 1/2(2.00kg)(v2)^2 - 1/2(2.00kg)(0)^2

Fd = 1/2(2.00kg)(v2)^2

wsin(theta) is the only force horizontaly:

(wsin(theta))(0.70m) = 1/2(2.00kg)(v2)^2

2 * ((2.00kg)(9.80m/s^2))(0.70)) = 2.00kg (v2)^2

v2 = 3.70m/s

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# Homework Help: Block of ice sliding down inclined plane - final speed

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