Block on an incline with Friction

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SUMMARY

The discussion centers on calculating the acceleration of a block with a mass of 2.29 kg on a 15.9° incline after an initial impulse. The coefficients of static and kinetic friction are μs = 0.579 and μk = 0.389, respectively. The user incorrectly applies Newton's Second Law by not accounting for the correct normal force, which is influenced by the incline angle. A proper force diagram is essential for accurately determining the forces acting on the block.

PREREQUISITES
  • Understanding of Newton's Second Law (F = ma)
  • Knowledge of static and kinetic friction coefficients
  • Ability to draw and interpret force diagrams
  • Familiarity with trigonometric functions related to angles
NEXT STEPS
  • Review the concept of normal force on inclined planes
  • Learn how to draw and analyze force diagrams for objects on inclines
  • Study the effects of static and kinetic friction in motion problems
  • Explore the application of trigonometric functions in physics problems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and inclined plane problems, as well as educators seeking to clarify concepts of friction and force analysis.

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Homework Statement



A block with a mass of m = 2.29 kg is at rest on an incline. The angle of the incline is θ = 15.9° with respect to the horizontal. The coefficient of static friction between the object and the incline is μs = 0.579, the coefficient of kinetic friction is μk = 0.389.

What would be the magnitude of the object's acceleration after an initial impulse set it in motion uphill on the incline?


Homework Equations


Newtons Second Law
F= ma
??

The Attempt at a Solution



[-(coefficient k)mg-mgsin(theta)]/m and then making that answer positive because it is a magnitude. Where am I going wrong here?
 
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You probably aren't actually drawing a force diagram. The frictional force is proportional to the normal force, which isn't mg. The normal force depends on the angle too.
 

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