The problem statement, all variables and given/known data A block with mass m = 7.4 kg slides down an inclined plane of slope angle 43.8 ° with a constant velocity. It is then projected up the same plane with an initial speed 3.10 m/s. How far up the incline will the block move before coming to rest? The attempt at a solution You need to find the force parallel of the block on the incline, so Fpara = mgsinθ Fpara = (7.4)(9.8)sin(43.8) Fpara = 50.194 N Acceleration down is a = F/m a = 50.194/7.4 a = 6.783 If the block begins moving up at Vi = 3.10 m/s, and Vf = 0, then Vf^2 = Vi^2 + 2ad 0 = 3.1^2 + (2)(-6.783)d d = -(3.1)^2 / -13.566 d = 0.708 This is not correct. Obviously, I'm doing this wrong, but I'm not sure of any other way to do it. I feel like having such a large acceleration down can't possibly be correct, and if that is indeed the case, how do I find acceleration of the block as it goes up the incline?