Block on incline with vertical force

In summary, the block slides down an inclined plane with a vertical force of 15 N applied to it. The acceleration of the block is downwards along the incline.
  • #1
robvba
27
0

Homework Statement


3.0-kg block slides on a frictionless 37° incline plane. A vertical force of 15 N is applied to the block. The acceleration of the block is?


Homework Equations


m*g*sin()


The Attempt at a Solution


3*9.8*sin(37) - 15 = 2.7
 
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  • #2
Assuming the vertical force is downwards, then the acceleration of the block is downwards along the incline. It would be more relevant to resolve forces along the incline.

The downward force and the weight of the block are in the same direction, so your expression for the weight applies equally to the downward force. The mass is 3kg.
So if you use Newton's second law F=ma, you would be able to figure out the acceleration, assuming the inclined plane is frictionless.
 
  • #3
What forces act on the block? What are their components parallel to the incline? What's the net force parallel to the incline?
 
  • #4
The figure shows a block on a 37 degree incline with a vertical arrow moving from the block upward (representing the applied force)
 
  • #5
robvba said:
The figure shows a block on a 37 degree incline with a vertical arrow moving from the block upward (representing the applied force)
OK, so the vertical force is upward. What is its component parallel to the incline? What is the component of the weight parallel to the incline?
 
  • #6
Doc Al said:
OK, so the vertical force is upward. What is its component parallel to the incline? What is the component of the weight parallel to the incline?

m*g*sin()
 
  • #7
robvba said:
m*g*sin()
That's the component of the weight. (Does it point up or down the incline?) What about the component of the applied vertical force?
 
  • #8
Doc Al said:
That's the component of the weight. (Does it point up or down the incline?) What about the component of the applied vertical force?

It points down. The applied points up.
 
  • #9
robvba said:
It points down. The applied points up.
Good. What's the component of the applied force parallel to the incline?
 
  • #10
Doc Al said:
Good. What's the component of the applied force parallel to the incline?

m*g*cos()?
 
  • #11
? ?
 

1. What is a block on incline with vertical force?

A block on an incline with vertical force is a common physics problem that involves a block or object resting on an inclined surface and being acted upon by a vertical force, usually due to the force of gravity.

2. How do you calculate the acceleration of a block on incline with vertical force?

The acceleration of a block on an incline with vertical force can be calculated using the formula: a = g(sinθ - μcosθ), where a is the acceleration, g is the acceleration due to gravity, θ is the angle of the incline, and μ is the coefficient of friction.

3. What is the role of the coefficient of friction in a block on incline with vertical force?

The coefficient of friction determines the amount of resistance between the block and the inclined surface. It is a measure of how easily the block will move or slide down the incline due to the force of gravity.

4. How does the angle of the incline affect the motion of the block on incline with vertical force?

The angle of the incline plays a crucial role in determining the acceleration and motion of the block. A steeper incline will result in a greater acceleration and faster motion of the block, while a shallower incline will result in a slower motion with less acceleration.

5. What real-life applications involve a block on incline with vertical force?

The concept of a block on incline with vertical force has many practical applications, such as calculating the motion of an object sliding down a ramp, determining the force needed to lift an object up an inclined plane, and understanding the motion of a car driving up and down a hill.

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