Block on incline with vertical force

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Homework Help Overview

The discussion revolves around a physics problem involving a 3.0-kg block sliding on a frictionless incline at a 37° angle, with a vertical force of 15 N applied to it. Participants are exploring the effects of this force on the block's acceleration.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to resolve the forces acting on the block, including the weight and the applied vertical force. Questions are raised about the components of these forces parallel to the incline and how they affect the block's acceleration.

Discussion Status

There is an ongoing exploration of the components of the forces acting on the block, with some participants suggesting the use of Newton's second law. The discussion is focused on clarifying the direction and impact of the forces involved, but no consensus has been reached yet.

Contextual Notes

Participants are considering the implications of the incline being frictionless and the direction of the applied vertical force, which is upward, in contrast to the weight of the block.

robvba
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Homework Statement


3.0-kg block slides on a frictionless 37° incline plane. A vertical force of 15 N is applied to the block. The acceleration of the block is?


Homework Equations


m*g*sin()


The Attempt at a Solution


3*9.8*sin(37) - 15 = 2.7
 
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Assuming the vertical force is downwards, then the acceleration of the block is downwards along the incline. It would be more relevant to resolve forces along the incline.

The downward force and the weight of the block are in the same direction, so your expression for the weight applies equally to the downward force. The mass is 3kg.
So if you use Newton's second law F=ma, you would be able to figure out the acceleration, assuming the inclined plane is frictionless.
 
What forces act on the block? What are their components parallel to the incline? What's the net force parallel to the incline?
 
The figure shows a block on a 37 degree incline with a vertical arrow moving from the block upward (representing the applied force)
 
robvba said:
The figure shows a block on a 37 degree incline with a vertical arrow moving from the block upward (representing the applied force)
OK, so the vertical force is upward. What is its component parallel to the incline? What is the component of the weight parallel to the incline?
 
Doc Al said:
OK, so the vertical force is upward. What is its component parallel to the incline? What is the component of the weight parallel to the incline?

m*g*sin()
 
robvba said:
m*g*sin()
That's the component of the weight. (Does it point up or down the incline?) What about the component of the applied vertical force?
 
Doc Al said:
That's the component of the weight. (Does it point up or down the incline?) What about the component of the applied vertical force?

It points down. The applied points up.
 
robvba said:
It points down. The applied points up.
Good. What's the component of the applied force parallel to the incline?
 
  • #10
Doc Al said:
Good. What's the component of the applied force parallel to the incline?

m*g*cos()?
 
  • #11
? ?
 

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