Block on Spring with Friction Problem

Click For Summary

Homework Help Overview

The problem involves a block of mass m moving towards a spring on a table with friction. The original poster is trying to determine how much the block compresses the spring and the average power generated due to friction during this compression. There is uncertainty regarding the necessity of the spring constant k for solving the problem.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to break the problem into sections and formulates an equation relating spring compression and friction. They question whether the spring constant k is needed to proceed with the solution.
  • Some participants confirm the need for k and suggest that the average power can be calculated using work done divided by time, while also discussing the relationship between force, work, and power.

Discussion Status

The discussion is active, with participants providing guidance on the necessity of the spring constant and clarifying the relationship between work done by friction and average power. There is acknowledgment of a potential typo in the original equation, and some participants have shared their own problem-solving approaches.

Contextual Notes

There is a mention of a possible typo in the original poster's equation and a discussion about the assumptions regarding the spring constant and the nature of friction in the problem.

weebedink
Messages
2
Reaction score
0

Homework Statement


A block of mass m is moving at a speed of v0 at a distance L away from a spring of on a table with coefficient of friction μk. How much does the block compress the spring? Determine the average power generated due to friction during the compression of the spring.

I'm not sure if there is a problem with the question or is it just my methods, but is there a spring constant K needed to solve this problem? Also how would I solve for the average power?

Homework Equations


W+Wfriction=ΔKE+ΔUspring

Wfriction=Ffrictionx=μkmgx

The Attempt at a Solution


I split the problem into three sections. When the spring is compressed, right after the block reaches the end of the spring, and when the block is a distance L away from the spring. From these positions I got two equations and combined them into this:

kx2-2μkmgx=m(v0+2μkgL)

Now if the k was given, I would just solve for x and that would be the compression of the spring. Am I missing something? or do I need a k to keep on going?

For the average power dissipated by friction, I would use the Wfrictionkmgx and then maybe integrate with respect to time or divide by time. Am I right in my assumption?
 
Physics news on Phys.org
Welcome to PF!
Yes, you sure do need k. The block will compress the spring more if k is smaller. The answer depends on k.

There must be a typo in your equation - the v should be squared, shouldn't it?
Otherwise, it makes perfect sense.
 
weebedink said:
Now if the k was given, I would just solve for x and that would be the compression of the spring. Am I missing something? or do I need a k to keep on going?

For the average power dissipated by friction, I would use the Wfrictionkmgx and then [STRIKE]maybe integrate with respect to time or[/STRIKE] divide by time. Am I right in my assumption?

You need the spring constant.
The average power is work done divided by time. The friction is a constant force, so its work along a distance x is W=μkmgx.
Find the time needed to stop the object.

The instantaneous power is P=Fv. You can get a rough estimate of the average power by using the half of the speed the object reaches the spring with.

ehild
 
There must be a typo in your equation - the v should be squared, shouldn't it?
Yeah my bad haha it is.

The average power is work done divided by time. The friction is a constant force, so its work along a distance x is W=μkmgx.
Find the time needed to stop the object.

Yeah I was able to solve using forces and kinematics.

Thank you so much for all of the help!
 
You are welcome.ehild
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
Replies
17
Views
2K
Replies
61
Views
4K
Replies
29
Views
3K
  • · Replies 52 ·
2
Replies
52
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
8
Views
6K
  • · Replies 14 ·
Replies
14
Views
2K