How can I determine the instant the block overcomes static friction?

[hutchphd]

Thanks, well done.

 

[TSny]

$\sqrt {\frac {2~20~0.0491 - 200~(0.0491)^2} { \frac {21} 5 (0.3)^2}}$ $≈ 1,252~rad/s$

Check the evaluation. (Maybe you already caught this.)