# Block pulled at an angle with friction

## Homework Statement

A 4.62 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 12.0 N at an angle θ = 33.0° above the horizontal.

The coefficient of kinetic friction between the block and the floor is 0.100. What is the speed of the block 3.10 s after it starts moving?

## Homework Equations

Fn = Uk * (m*g - F*sin$$\theta$$)

F = ma

## The Attempt at a Solution

I solved for Fn and got Fn = 3.87. I assume I need to solve for acceleration and then get velocity but I am not sure.

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PhanthomJay
Homework Helper
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## Homework Statement

A 4.62 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 12.0 N at an angle θ = 33.0° above the horizontal.

The coefficient of kinetic friction between the block and the floor is 0.100. What is the speed of the block 3.10 s after it starts moving?

## Homework Equations

Fn = Uk * (m*g - F*sin$$\theta$$)
You mean that's the friction force
F = ma

## The Attempt at a Solution

I solved for Fn and got Fn = 3.87. I assume I need to solve for acceleration and then get velocity but I am not sure.
You correctly solved for the friction force, so yes, continue to solve for the acc. in the horiz direction.

I'm still stuck, do I use F = ma to find accel and my F = 3.87? I tried it that way but got the wrong answer.

PhanthomJay