A 4.62 kg block located on a horizontal floor is pulled by a cord that exerts a force F = 12.0 N at an angle θ = 33.0° above the horizontal.
The coefficient of kinetic friction between the block and the floor is 0.100. What is the speed of the block 3.10 s after it starts moving?
Fn = Uk * (m*g - F*sin[tex]\theta[/tex])
F = ma
The Attempt at a Solution
I solved for Fn and got Fn = 3.87. I assume I need to solve for acceleration and then get velocity but I am not sure.