Block Slides Down Giant Globe in Italy

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SUMMARY

The discussion centers on the physics of a block sliding down a giant globe in Italy, specifically addressing the forces acting on the block. Participants confirm that the globe does not exert significant gravity, and the only force acting on the block is Earth's gravity. They conclude that once the block leaves the globe, friction is the only opposing force, and centripetal acceleration cannot be zero as the block travels along a circular path before detaching. The conversation also touches on the relationship between kinetic and potential energy during the block's descent.

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  • Understanding of Newton's laws of motion
  • Familiarity with gravitational forces and their effects
  • Knowledge of centripetal acceleration concepts
  • Basic principles of kinetic and potential energy
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  • Learn about centripetal force and its applications in circular motion
  • Explore the concepts of friction and its role in motion dynamics
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Homework Statement


there is a block sliding down a big globe in Italy.


Homework Equations



uhh

The Attempt at a Solution



does the globe have its own gravity?

i'm thinking its A and C.
 

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No, the globe doesn't have any significant gravity of it's own. Just use the Earth's gravity.
 
and so it is a and c

becuz

once the block leaves the globe

nothing is pushing the box up (but friction) and nothing is slowing the box down in the horizontal direction (but friction)

and so the only force is the earth?

right?
 
Yes, the only force is the Earth's gravity. (So no friction.)
 
ok the next questions asks about about momentum

im thinking

centripetal acceleration cannot be zero becuz

is it zero? i don't think so becuz its traveling on a circular path prior to leaving the globe

normal force must be zero becuz nothing is pushing up

the net acceleration is down and its velocity is going right and down

the kinetic energy cannot equal its potential energy becuz you cannot tell if the box is halfway down the globe right?

so the only choice is normal force right?

B
 

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