Bohr Model Postulates: Understand Discrete Angular Momentum Orbits

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SUMMARY

The discussion centers on the derivation of discrete angular momentum orbits in the Bohr model of the hydrogen atom, specifically the equation m*v*r=n*h/(2*pi). It clarifies that Bohr's conclusions were based on his understanding of existing formulas for discrete wavelengths and the classical model of electron orbits. De Broglie's approach, rooted in wave mechanics, aligns numerically with Bohr's findings but stems from a different theoretical framework. The full implications of wave mechanics were later explored by David Bohm in his work "Quantum Theory."

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  • Understanding of the Bohr model of the hydrogen atom
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  • Study the derivation of the Bohr model equations for hydrogen
  • Explore de Broglie's wave-particle duality and its implications
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Bassalisk
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Hello,

I am interested if anybody knows, how did Bohr came to the conclusion that only discrete angular momentum orbits are stable? In other words,

m*v*r=n*h/(2*pi)

and how did de Broglie came to the same conclusion, just through another way 2*pi*r=n*h/(m*v)

Thanks
 
Last edited:
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Hi Bassalisk,

Bohr didn't come to that conclusion. He was already familiar with the various formulas for determining the ratios between the various discrete wavelengths or frequencies of emission of a hydrogen atom. He apparently intuitively recognized the pattern could likely be derived from a model of the electron orbiting the proton and set about creating the most simple model possible using energies (kinetic and potential) balanced in a standard classical model.

De Broglie's analysis is based on wave mechanics and phase invariance in any frame of reference. Numerically, it happened to coincide with Bohr's model (for hydrogen only) But a full analysis of how wave mechanics restricts the possible modes of radiation didn't really come until Bohm had studied and documented the situation ("Quantum Theory" -David Bohm) That particular book is general and doesn't involve his variant of "Pilot Wave" theory.
 
Last edited:
Thank you very much, you answer was very helpful!
 

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