Bohr Radius and Ground State Energy

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Homework Help Overview

The discussion revolves around finding the Bohr radius and ground state energy for a hydrogen atom using the potential energy expression and the uncertainty principle. Participants are exploring the relationship between kinetic energy and the Bohr radius in the context of quantum mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply the uncertainty principle to express kinetic energy in terms of the Bohr radius but expresses confusion about the process. Other participants suggest using the virial theorem as a potential method to find the Bohr radius, while some question the necessity of additional information.

Discussion Status

Participants are actively engaging with the problem, with some suggesting alternative approaches like the virial theorem. There is acknowledgment that different interpretations of the theorem may exist, and while some find it helpful, others remain uncertain about its application to the problem.

Contextual Notes

There is mention of specific constraints regarding the use of the virial theorem and its applicability to stationary states, which may affect the approach to solving the problem. The original poster also notes a lack of clarity regarding the relationship between the uncertainty principle and the kinetic energy expression.

davesface
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Homework Statement


Given the potential energy V(r)=-\frac{1}{4\pi \epsilon_0}\frac{e^2}{r} (where e is the unit charge), use the uncertainty principle \Delta x \Delta p \geq \hbar to find the Bohr radius r_B for a hydrogen atom and the ground state energy E_0.

Hint: write down the kinetic energy in terms of r_B using the uncertainty principle.

Homework Equations


-TISE: -\frac{\hbar^2}{2m}\frac{d^2u}{dr^2}+[V+\frac{\hbar^2}{2m}\frac{l(l+1)}{r^2}]u=Eu, where u(r)=r*R(r) and R(r) is the radial component of the separable wave function \Psi.
-Alternatively, {V}_{eff} =V(r)+\frac{\hbar^2}{2m}\frac{l(l+1)}{r^2}

The Attempt at a Solution


The hint is really what throws me off. Finding the ground state energy is done out entirely in the textbook, but there is nothing about the modified uncertainty relation or writing the kinetic energy in terms of the Bohr radius before finding it.

I tried doing that, so T=\frac{p^2}{2m}=\frac{\hbar^2}{2mx^2} if we assume equality in the uncertainty relation. Then I plugged that into an equation for the defined quantity \kappa=\frac{\sqrt{-2mE}}{\hbar}=\frac{i}{x}. Do I just plug in r_B for x now? I just don't see at all how doing that, if it's even correct, is leading closer to finding r_B.

EDIT: As an added note, I tried reverse engineering the solution: r_B=\frac{4\pi \epsilon_0\hbar^2}{m_e e^2}=\frac{-\hbar^2}{m_e r V(r)}, but that didn't make the problem any clearer to me.
 
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Hmm, I'm not sure how you can find the Bohr radius without an additional piece of information. If you use the virial theorem, which says <T> = -<V>/2, you can then solve for a0.
 
Our book only mentions the special cases of the virial theorem for stationary states ,2&lt;T&gt;=&lt;x\frac{dV}{dx}&gt;, and stationary states of the harmonic oscillator, &lt;T&gt;=&lt;V&gt;.

Even if I use your version of it, though, I don't see how that helps.
 
For a potential of the form rn, the virial theorem reduces to what I said.

http://en.wikipedia.org/wiki/Virial_theorem

In your expression for T after you substituted with the uncertainty principle, set x to the Bohr radius. Similarly, in the potential, set r to the Bohr radius. Then solve for the Bohr radius.
 
Wow, that theorem made it a much easier problem to solve. Thanks very much.
 

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