Calculating Boiling Point of a Solution: A Joke Problem for Extra Credit

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The professor assigned a humorous extra credit problem requiring the calculation of the boiling point of a 1:1:1 solution of benzene, pentane, and ethylene in a pressurized neon tank at 6 atm, using only pen, paper, and a ham. The initial attempt at solving it involved averaging the boiling points of the individual components, but the problem is intended as a joke. Participants noted the absurdity of the requirements, questioning the practicality of using a ham and whether vegetarians would object. The discussion quickly turned lighthearted, leading to the conclusion that it was unnecessary to pursue serious responses. Ultimately, the thread was closed due to the joking nature of the problem.
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Homework Statement
Extra credit problem
Relevant Equations
ΔHo −TΔSo=0
The professor posted a take-home problem for us to solve for extra credit.

Extra credit problem:
Using nothing but pen, paper and a ham, calculate the boiling point of 1:1:1 solution of benzene, pentane, and ethylene in a pressurized tank filled with neon at 6 atm pressure. The Answer must be accurate to 14 significant figures. Hint: account for all the degrees of freedom within the system.How far I've gotten to solving the problem:

(boiling point of benzene + boiling point of pentane + boiling point of ethylene) / 3 = boiling point of the solution accurate to one significant figure.

It's a joke problem. I'm joking.
 
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docnet said:
Using nothing but pen, paper and a ham
Doesn't that exclude using PF 🤔?
 
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Likes berkeman and docnet
docnet said:
and a ham
Wouldn't vegetarians object!
 
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docnet said:
It's a joke problem. I'm joking.
Then you don't need us to waste our time trying to reply. Thread is closed.
 
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Likes jim mcnamara
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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