1. The problem statement, all variables and given/known data When benzene freezes at 5.5 C its density changes from 0.879 g cm-3 to 0.891 g cm-3. Its enthalpy of fusion is 10.59 kJ mol -1. Estimate freezing point of benzene at 1000 atm 2. Relevant equations Solid liquid boundary: p=p*+ΔHfus/ΔV ln(T/T*) 3. The attempt at a solution From the equation I can solve for T which I do not have a problem with. For ΔV fus I thought to take the the difference of the densities and then using the molar mass of benzene, 78.1 g/mol, get ΔVm in cm-3.This is then converted to m-3. I made the assumption that the first part is occurring under normal conditions, so 1 atm for the freezing point at 5.5 C given in the problem. I think assuming 1 atm is my biggest mistake when solving this problem because I think that everything else is just plugging in the values.