Boiling points and hydrogen bondings

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SUMMARY

The boiling points of hydrogen halides are influenced by hydrogen bonding and molecular size. HF has the highest boiling point at 20°C due to strong hydrogen bonds, while HCl, HBr, and HI have lower boiling points of -85°C, -67°C, and -35°C respectively. The expected order of boiling points based on molecular weight (HCl > HBr > HI) is contradicted by the stronger hydrogen bonding in HF. Factors such as dipole moments, electronegativity, and van der Waals forces also play significant roles in determining boiling points among these compounds.

PREREQUISITES
  • Understanding of hydrogen bonding and its requirements, specifically with electronegative atoms.
  • Knowledge of molecular polarity and dipole moments.
  • Familiarity with van der Waals forces and their influence on boiling points.
  • Basic concepts of molecular size and its effect on intermolecular forces.
NEXT STEPS
  • Research the specific requirements for hydrogen bonding in molecules, focusing on electronegativity.
  • Study the effects of molecular size on van der Waals forces and boiling points.
  • Explore the relationship between dipole moments and boiling points in various chemical compounds.
  • Investigate the periodic trends in boiling points among halides and other groups in the periodic table.
USEFUL FOR

Chemistry students, educators, and professionals interested in understanding the factors affecting boiling points and intermolecular interactions in hydrogen halides.

kasse
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Homework Statement



Explain the boiling points of HF, HCl, HBr nd HI


The Attempt at a Solution



The boiling points are:

HF: 20 C
HCl: -85 C
HBr: -67 C
HI: -35 C

The hydrogen bondings between H and F are stronger than other hydrogen bondings. Therefore HF has the highest boiling point. But then I'd expect the order to be HCl > HBr > HI; not the opposite. How can that be explained?
 
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do H-bonds really occur in all the hydrogen halides? what are the requirements for an H-bond to be formed?
 
kasse said:

Homework Statement



Explain the boiling points of HF, HCl, HBr nd HI


The Attempt at a Solution



The boiling points are:

HF: 20 C
HCl: -85 C
HBr: -67 C
HI: -35 C

The hydrogen bondings between H and F are stronger than other hydrogen bondings. Therefore HF has the highest boiling point. But then I'd expect the order to be HCl > HBr > HI; not the opposite. How can that be explained?

This is somewhat of a trick question you really need to observe the relations between the intermolecular and intramolecular-what's especially important here is the polarizability with additional regard to dipole moments due to electronegativity- attractions in this case.
 
Kushal said:
what are the requirements for an H-bond to be formed?

No idea. My book only says that H-bonds occur between molecules when a H-atom bonds with an electronegative atom.
 
it should've been said 'a VERY elctronegative atom'. only N, O and F can form H-bonds. does this help you?!
 
Yes, thanks.
 
i was more expecting you to explain the trends in boiling point using this information than saying thanks.

:)
 
This is actually a very hard trick question. I know I had some problem with it in the first chem-course at my university. But, it is a very multifaceted question. And also a rather tricky one, because many factors play their part in a complex thing like boiling points. Dipole-momentum, electronegativity, bond-lengths and such. But one thing that often is overlooked and why this is a hard question is about the quantum number, the amount of shells and electrons in the atom.

When a atom has a lot of electrons, they also increase the the amounts of van-der-waalforces in the molecule. And if the amount goes up for a given timeperiod, the strength of the bond also goes up.

Which means that downward in the halide-group, you always get stronger bonds (van-der-waals) due to larger molecules. This is something you can generalize on the atomic table and periods. But remember, that it is a lot of exceptions to this rule. Which is why chemistry is a bit tricky.
 

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