Boltzmann equation - Why does theta = 5040/T

[Physics Dad]

Hi,

I am working on a Boltzmann equation question and I know that the solution I am looking for is that:

log(n_ij/n_ji)=log(g_ij/g_ji)-E_ij(eV)(5040/T)

The only thing I don't understand is why log(e^-E_ij/kt) = θ = 5040/T

From what I have read in textbooks, it is just a given, but I really want to know why!

Any help gratefully received!

Thank you

 

[Lord Jestocost]

log(e^{-E_ij /kT} ) = E_ij* θ where θ = log(e) / (kT) = 5040 / T when E_ij is in eV

 

[Physics Dad]

Thank you for the reply. It was the log(e) that was confusing me, all sorted now!