- 14,922
- 28
What is a property of a set?
Is it the case that [itex]\forall a : a \in \{\_\}[/itex]?
Is it the case that [itex]\forall a : a \in \{\_\}[/itex]?
Originally posted by Hurkyl
I think that if you're going to talk about a universal set, you're going to need to explicitly demonstrate why the usual proof of [itex]X \neq \mathcal{P}(X)[/itex] fails, and how the usual constructions of paradoxes fails. (such as the set of all sets that don't contain themselves)
if a well formed formula leads to a contradiction, then that is not a subset.
Originally posted by Organic
General Information Framework (GIF) set theory
i'm going to have to look at this further. since you replaced it with the word false, i'd just like to say that things are not exclusively true or false anymore but possibly the third truth value. just for everyone else, i'll put what i know about 3 valued logic here:In what I have read (long ago) on multivalued logics, the classical paradoxes in binary logic can fairly straightforwardly be extended to multi-valued logic.
For instance, [itex]S := \{ x | x \in x\; \mbox{is not true} \}[/itex] sufficies for at least one ternary logic.
it would require quantifying over wffs as far as i can see. this would be added somewhere:and there's the rub; we need to know what a "safe" set of formulas is. This is a purely metamathematical concern; I can't see any way it could be written formally.
i'll look at your S. thanks for submitting it.Anyways, it is an interesting exercise to formally write up your ternary logic and see if it really sufficies. I bet that replacing "[itex]p \notin q[/itex]" in Cantor's argument with "[itex]p \in q[/itex] is false or <name of third logical value>", then you can still derive a contradiction.
i agree that complete can't, but why "all?" the quantifier is as in "all sets". why can we not use this? the "therefore" seems to be a non sequitor: the conclusion doesn't follow from the premise.Infinitely many objects ( {a,b,…} ) cannot be completed, therefore words like ‘all’ or ‘complete’ cannot be used with sets that have infinitely many objects.