Boost Your Cosine-Sine Isotherm Sketching Skills | Expert Tips & Guidance

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SUMMARY

This discussion focuses on sketching isotherms for the temperature field defined by the equation $T=\cos(x)\sinh(y)$. To create isotherms, one must solve the equation $C=\cos(x)\sinh(y)$ for various constants $C$. The solution for $y$ is given by $y=\text{arcsinh}(C\sec(x))$. By selecting multiple values for $C$ and plotting the resulting function, users can effectively visualize the isotherms in the $(x,y)$ plane.

PREREQUISITES
  • Understanding of hyperbolic functions, specifically $\sinh(y)$ and $\sec(x)$.
  • Familiarity with the concept of isotherms in thermodynamics.
  • Basic knowledge of graphing functions in a Cartesian coordinate system.
  • Proficiency in using mathematical software or graphing tools for plotting functions.
NEXT STEPS
  • Learn how to use graphing software like Desmos or GeoGebra to visualize functions.
  • Study the properties and applications of hyperbolic functions in mathematical modeling.
  • Explore the concept of isotherms in different fields, such as physics and engineering.
  • Investigate the implications of temperature fields in thermodynamics and fluid dynamics.
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Students and professionals in mathematics, physics, and engineering who are interested in visualizing temperature distributions and understanding isothermal processes.

brunette15
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I am trying to sketch isotherms of the field cos(x)sinh(y). I am not sure how to begin with this. Can someone please help/hint me through what i have to do?
 
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Presumably, you actually have a temperature field, right? That is, $T=\cos(x)\sinh(y)$. In that case, you want to sketch whole bunch of curves in the $(x,y)$ plane of the form $C=\cos(x)\sinh(y)$. Why a constant? Because you're after the isotherms - the prefix "iso" meaning "same". In fact, you can solve this equation for $y$:
\begin{align*}
C&=\cos(x)\sinh(y) \\
\sinh(y)&=C \sec(x) \\
y&=\text{arcsinh}(C\sec(x)).
\end{align*}
So, pick a few $C$'s, plot the above function, and you've got your isotherms.
 
Ackbach said:
Presumably, you actually have a temperature field, right? That is, $T=\cos(x)\sinh(y)$. In that case, you want to sketch whole bunch of curves in the $(x,y)$ plane of the form $C=\cos(x)\sinh(y)$. Why a constant? Because you're after the isotherms - the prefix "iso" meaning "same". In fact, you can solve this equation for $y$:
\begin{align*}
C&=\cos(x)\sinh(y) \\
\sinh(y)&=C \sec(x) \\
y&=\text{arcsinh}(C\sec(x)).
\end{align*}
So, pick a few $C$'s, plot the above function, and you've got your isotherms.

Thankyou so much :)
 

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