Born-Haber Cycle: Formation of a Chlorine Atom

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In the Born-Haber cycle, the formation of a chlorine atom from a chlorine molecule involves breaking the Cl2 bond, which requires 244 kJ for one mole. The equation (1/2)Cl2 → Cl(g) reflects that only half a mole of Cl2 is needed to produce one mole of chlorine atoms, thus the energy is halved to 122 kJ. This approach clarifies that the bond energy is divided because the calculation is based on moles rather than individual atoms. Understanding this concept is crucial for accurately applying the Born-Haber cycle in thermodynamic calculations. The discussion emphasizes the importance of mole-based reasoning in energy calculations.
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Homework Statement


I don't actually need help with an entire problem, I just can't seem to figure out what goes on when an atom is formed from a molecule in a Born-Haber cycle.

For example:
The formation of a chlorine atom from a chlorine molecule
(1/2)Cl2 → Cl(g) ΔH = (1/2) x bond energy of Cl2 = +122 kJ

Homework Equations

The Attempt at a Solution


Why is the bond energy being halved? It you have a Cl2 molecule, and you need 244 kJ to break the bond into two Cl atoms. Why would the formation of a Cl atom be only half of that then?
 
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Doesn't that (1/2) factor mean something?
 
Here, it might be more useful to think in terms of moles. Reacting one mole of Cl2 takes 244 kJ, and making one mole of chlorine atoms requires reacting 0.5 moles of Cl2.
 

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