Boundary conditions for wave fixed at one end

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SUMMARY

The discussion focuses on the boundary conditions for a wave on a string fixed at one end (x=0) and free at the other end (x=l). It establishes that the first derivative of the displacement with respect to x at the fixed end, \(\frac{\partial y(0,t)}{\partial x}=0\), is indeed zero, confirming that the string does not move at that point. Additionally, the second derivative, \(\frac{\partial^2 y(0,t)}{\partial x^2}=0\), is not applicable at the fixed end, as the boundary condition only requires the first derivative to be zero.

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  • Understanding of wave equations and boundary conditions
  • Familiarity with partial differential equations
  • Knowledge of string dynamics and fixed/free boundary scenarios
  • Basic calculus, particularly derivatives
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  • Study the wave equation in one dimension
  • Explore fixed and free boundary conditions in wave mechanics
  • Learn about the implications of boundary conditions on wave behavior
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Physicists, engineers, and students studying wave mechanics, particularly those focusing on string dynamics and boundary condition analysis.

mrausum
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For a string fixed at x=0 and free at x=l I know [tex]\frac{dy}{dx}(l,t)=0[/tex] (d's are meant to be partials) but what is the other boundary associated with the end of the string? Is the second derivative also equal to 0?
 
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[tex]\frac{\partial y(0,t)}{\partial x}=0[/tex] must also be true since it is fixed. Also [tex]\frac{\partial^2 y(0,t)}{\partial x^2}=0[/tex]
 

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