Bouyancy Question: Two weights on strings, with one weight submerged

Click For Summary

Homework Help Overview

The discussion revolves around a buoyancy problem involving two weights on strings, with one weight submerged in water. The original poster is attempting to express a relationship involving the density of water and the tensions T1 and T2 in the context of buoyancy forces.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive an equation that relates the density of water to the tensions in the strings but struggles with the algebraic manipulation. Some participants suggest defining variables to simplify the problem and question the use of certain symbols, while others inquire about alternative methods to express the relationship without direct substitution.

Discussion Status

Participants are actively engaging with the original poster's attempts, providing insights and suggestions for variable definitions. There is a productive exchange of ideas, with some guidance offered on formatting and expressing equations more clearly. However, there is no explicit consensus on the final form of the equation being sought.

Contextual Notes

The original poster expresses difficulty with the terminology and formatting, indicating a learning curve in understanding the physics concepts and mathematical representation involved in the problem.

norcal36
Messages
8
Reaction score
0
Homework Statement
You have two scales with a weight suspended from them on a string. Scale one has a tension of T1 and scale two has its mass submerged in water with tension T2. If you have T2<T1, find the density of the weight in terms of only density of the water, T1 and T2.
Relevant Equations
Density = mass/volume
Volume = mass/density
mass = density*volume
Buoyancy = Density of liquid*Volume Displaced*gravity
Hi new to the physics world and the symbiology is hard to understand completely. Attached is the work I've done to a final solution but I can't seem to get the answer in terms of only density of water and T1 and T2. Thank you for any assistance.

[ Mentor Note -- Word file replaced with a screenshot. Please use PDF or JPEG format for posting files. ]

1575213822688.png

 
Last edited by a moderator:
Physics news on Phys.org
Hello norcal, ##\qquad## :welcome: ##\qquad## !

If you can use MS equation, you can use ##LaTeX## too -- makes ist much easier to assist :rolleyes:

I love your word 'symbiology'
-- in this context I propose you create a variable ##V## for the volume of the weight. Definition of density ##\rho## (using a ##\delta## is confusing to others) is ##m = \rho V## . Rings a bell in the algebraic treatment ? [edit] greyed out after a cup of coffee and a decent read of your word doc :smile:

[edit] never mind, you are nearly there already: your last line reads $$\rho_b = {mg\; \rho_w\over T_1-T_2}$$ and to get it in the required form, you need something else for ##mg##. Guess ...
 
Last edited:
  • Like
Likes   Reactions: norcal36
Thank you for that insight. With that I do get the correct answer with replacing the mg with T1. However, is there a way to manipulate the equation without just replacing that mg with T1? Again thank you for the insight!
 
Also I apologize for my inexperience with formatting . I don't know what LaTeX is and only way I could show my work was to use Word Possessor.
 
norcal36 said:
Also I apologize for my inexperience with formatting . I don't know what LaTeX is and only way I could show my work was to use Word Possessor.
Click the link @BvU provided in post #2 for LaTeX.
Or use the pull-downs above the text entry panel:
##\sqrt x## for Greek letters, math symbols..
... for subscripts and superscripts.
 
  • Like
Likes   Reactions: norcal36
Thanks!
 

Similar threads

  • · Replies 75 ·
3
Replies
75
Views
7K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 152 ·
6
Replies
152
Views
11K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 19 ·
Replies
19
Views
10K
Replies
17
Views
6K
  • Sticky
  • · Replies 0 ·
Replies
0
Views
12K
  • · Replies 54 ·
2
Replies
54
Views
8K
  • · Replies 33 ·
2
Replies
33
Views
9K